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-11x+3=-4x^2
We move all terms to the left:
-11x+3-(-4x^2)=0
We get rid of parentheses
4x^2-11x+3=0
a = 4; b = -11; c = +3;
Δ = b2-4ac
Δ = -112-4·4·3
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{73}}{2*4}=\frac{11-\sqrt{73}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{73}}{2*4}=\frac{11+\sqrt{73}}{8} $
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